Saturday, 21 April 2018

Rajasthan Elementary Education has liberated a job advertisement regarding REE Recruitment 2018. The organization invites applications from Skilled and capable candidates to fill up the 26000 posts of Teacher. Desired aspirants who are willing to secure their job may apply by submitting online application form on or before the last date (30th April 2018).
To get further information regarding REE Recruitment 2018, you should visit the below advertisement where you will get information about Selection Procedure, Pay Scale, Application Fee and much more.

Information of REE Recruitment 2018:

Organization / Division Name: Rajasthan Elementary Education

Job Role: Teacher

Looking for => Teaching Jobs

Number of Vacant Posts: 26000

Post Wise Detailed Information:

1. Teacher Cat-3,Level-I (TSP Area)- 5503
2. Teacher Cat-3,Level-I (Non TSP Area) - 20497

Primary Qualification: Individuals looking for this job should hold 12th or Graduation Degree with Diploma in Elementary Education/B.El.Ed/ TET/RTET/REET from an accredited board / university / institute.

Age Limitation:
  • Aspirant’s age should be in the range of 18 - 40 Years counted from 01-01-2019.
  • Relaxation in age limit is provided to the candidates belong to reserved category, according to the organizational regulation.
Selection Criteria:
    Contenders looking for this job will be chosen according to their performance in RTET/REET Marks , Merit List.
Application Fee:

Salary and Pay Scale: Selected candidates will get the attractive salary package of Rs. 23,700/- Per month

How to Apply: Aspirants should visit the official website of the organization i.e. and fill online application form with all details regarding your name, address, qualification details, experience details, upload photograph & signature etc and submit online form before 30th April 2018

Important Date:
Starting Date / Ending Date for Online Application form Is :14-04-2018 to 30-04-2018.

official Website :



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